Answer to POW #8:

After multiplying both sides of the equation by 6, and then by 6^x, and doing some easy algebra, we arrive at an equation that is quadratic in 6^x: (6^x)^2 - 12(6^x) + 1 = 0 After using the quadratic formula and doing some other elementary operations, we arrive at two solutions (I apologize for the ugly typing): x = ln(6+sqrt{35})/ln(6) and x = ln(6-sqrt{35})/ln(6)